Hi,
Consider the following code:
a = 10
b = 1:10
Obviously,
c = a .= b
works just fine. But I have more complex expressions and do not wish to spend my time adding dots everywhere. So I tried:
@. D = a + b
However, this produces the error that D is not defined. Why is that? I would expect D to be a vector.
ERROR: UndefVarError: D not defined
Stacktrace:
[1] top-level scope at none:0
1 Like
klaff
2
c = a .= b doesn’t work, but I suspect you meant c = a .+ b, which does.
However, @. D = a + b is the same as D .= a .+ b which tries to do an in-place assignment to D.
If you first do D = zeros(10), then @. D = a + b will work.
3 Likes
Mason
3
The syntax that would do what you expect is
D = @. a + b
which creates an array D instead of trying to do in-place assignment to an existing array.
5 Likes