New syntax for Ac_mul_B!

linearalgebra

#1

His

I am trying to update an old code to Julia 1.0. I have some troubles finding the new way of doing

Ac_mul_B!(h, V, w)
h = Ac_mul_B(V, w)

Can someone help me please?

Thank you,


#2
mul!(h, V', w) 
h = V' * w

#3

Thanks!!

I have also A_mul_B!(AV.curr, A, V.curr)

Where can I find these translations so I don’t bother too much?


#4

You can use 0.7 - it has the same features as 1.0, but shows deprecations.