Both Calculus.jl and SystmUtils.jl have a simplify funtction. If I have code like. using Calculus using SystemUtils differentiate("x^2+65x^58+7-63") simplify(ans) how do in know which simplify it would use?

I am not an expert on this stuff, but I imagine it would depend on the argument type. The Calculus package make define simplify(::T1) while SystemUtils may define the method simplify(::T2) where T1 and T2 are types. So when you call simplify(ans) it depends on what the type is of ans. Now if both …

Prefix the function name with the module name: Calculus.simplify.

Perfect! then I can compare outputs! I didn’t like the results of Calculus.jl simplifications, and hope that SymbolicUtils will do a better job. I’m also interested in comparing Reduce.jl (but I can’t find how to simplify it the documentation), and Maxima.jl(Maxima simplifies nice, but I need a .bar…

@Wikunia is actually working on a project that should help with this called Seahawk.jl (link: https://github.com/Wikunia/Seahawk.jl ). He could probably explain more about it than I could. :slight_smile:

Going back to the question in the title, you could have used the which macro, which tells you where the method being called comes from: julia> @which sum(rand(10)) sum(a::AbstractArray; dims) in Base at reducedim.jl:722

Seahawk can be used if you don’t know the name of the function. In this case you want to use @which

Thank’s I’ll try to remember that.

Knowing what package a function is from?

General Usage

oxinabox October 29, 2020, 9:30pm 6

Calculus.jl is ancient and should not be used

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Knowing what package a function is from?

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