>> val = zeros(3, 3); >> row = zeros(3, 3); >> A = [1 2 3; 6 5 1; 1 7 4]; [val(1, :), row(1, :)] = max(A) val = 6 7 4 0 0 0 0 0 0 row = 2 3 3 0 0 0 0 0 0 How can I get the max value and row number and save them.

julia> vals, idx = findmax(A, dims=1) ([6 7 4], CartesianIndex{2}[CartesianIndex(2, 1) CartesianIndex(3, 2) CartesianIndex(3, 3)]) julia> vals 1×3 Matrix{Int64}: 6 7 4 julia> idx 1×3 Matrix{CartesianIndex{2}}: CartesianIndex(2, 1) CartesianIndex(3, 2) CartesianIndex(3, 3) If you need the ro…

Dear @skleinbo , how can I transform this matlab code into Julia code. Here is the MATLAB code. >> xx = zeros(2, 3) xx = 0 0 0 0 0 0 >> yy = zeros(2, 3) yy = 0 0 0 0 0 0 >> location = [1 2 3; 2 3 4] location = 1 2 3 2 …

You can use LinearIndices and CartesianIndices to convert between linear and cartesian indices. Edit: Ah, sorry, didn’t see you had discovered that already. You need to convert the cartesian indices to a tuple before indexing first, like the error suggests. Maybe xx[1,:] .= first.(Tuple.(Cartesian…

I try to use loop . julia> for i in 1:2, j in 1:3 xx[i, j] = CartesianIndices((2, 2))[location[i, j]][1] end julia> for i in 1:2, j in 1:3 yy[i, j] = CartesianIndices((2, 2))[location[i, j]][2] end julia> xx 2×3 Matrix{Float64}: 1.0 2.0 1.0 2.0 1.0 2.0 jul…

Thanks so much.This solves my problem.

Does Julia have the same function ind2sub or sub2ind? I think CartesianIndices or LinearIndices is worse than matlab function ind2sub.

@skleinbo I have another problem. I have convert the results to Int, but why the type is still Float64? pol_ind_kp[iak_state, :] = Int.(first.(Tuple.(CartesianIndices((nk, na))[Int.(location[iak_state, :])]))) typeof(pol_ind_kp) Matrix{Float64} (alias for Array{Float64, 2})

I have solved the problem by myself. I forget to set the zeros matrix Int when I define the pol_ind_kp.

Loops aren’t bad. They’re often the best way to solve a problem.

Thanks for your reply. But I think loops may take a very long time.

How can I transform this matlab code into Julia

General Usage

skleinbo May 20, 2022, 4:47pm 9

Not for a long time PSA: replacement of ind2sub/sub2ind in Julia 0.7+

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How can I transform this matlab code into Julia

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