ArgumentError while using ```enumerate(CSV.File())```: "..." is not a valid file

General Usage
1 
julia> for (i,row) in enumerate(CSV.File("/home/devel/Desktop/SDP_me/example/input/misc.csv"))
           println(i)
       end
ERROR: ArgumentError: "/home/devel/Desktop/SDP_me/example/input/misc.csv" is not a valid file
Stacktrace:
 [1] #File#1(::Int64, ::Bool, ::Int64, ::Nothing, ::Int64, ::Nothing, ::Bool, ::Nothing, ::Bool, ::Array{String,1}, ::String, ::String, ::Bool, ::Char, ::Nothing, ::Nothing, ::Char, ::Nothing, ::Nothing, ::Nothing, ::Nothing, ::Nothing, ::Dict{Type,Type}, ::Symbol, ::Bool, ::Bool, ::Bool, ::Bool, ::Base.Iterators.Pairs{Union{},Union{},Tuple{},NamedTuple{(),Tuple{}}}, ::Type, ::String) at /home/devel/.julia/packages/CSV/eWuJV/src/CSV.jl:135
 [2] Type at /home/devel/.julia/packages/CSV/eWuJV/src/CSV.jl:135 [inlined]
 [3] top-level scope at ./none:0

julia> for (i,row) in enumerate(CSV.File("/home/devel/Desktop/SDP_me/example/input/map.csv"))
           println(i)
       end
1

I checked the file, it’s there safe and sound. So I was deeply confused. (cry…) Can anyone please help me?

2

That error comes from the very first argument check in the function and it uses Base.isfile to check if the file input is indeed a valid file, so it seems that something is indeed wrong with your file (you can check this yourself by just doing isfile(file) from the REPL).

I mean, from the shell itself, can you navigate to that directory and do ls to list the contents of the directory? Maybe it’s a read permission issue? Just throwing out ideas here.

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