Hi all,
it is just a curious question. I am calculating k
from this
\int_{0}^{180} kx^{2} (180 - x) dx = 1
solving for k I should obtain \frac{1}{87,480,000} but why the answer contains 1-element Vector? instead of just the number?
using SymPy
@syms x, k
a,b = 0, 180
k1 = solve(integrate(k*(x^2)*(180-x),(x,a,b)) ~ 1, k)
1-element Vector{Sym}:
1/87480000
jling
February 21, 2023, 5:57am
2
that’s just how the interface works. My guess is to make type stable – i.e. you don’t get Sym
vs. Vector{Sym}
depending on how many variables you have, which is a runtime property
4 Likes
There is this problem I try:
k1::Vector
1-element Vector{Sym}:
95802719.0924019
k1::Int64
TypeError: in typeassert, expected Int64, got a value of type Vector{Sym}
Stacktrace:
I want to turn k1
into integer or float… how?
I’m a big fan of only(k1)
in this situation. It’s the same thing as k1[1]
except it will throw an error if length(k1) != 1
.
3 Likes