Ways of using constructor of a parametric type

[Tamas_Papp]

Nope, this is intended behavior. You are defining Bar(...) and Baz{T}(...) where T functions (which happen to be constructors), but not the other ones you are trying to call. See

Anybody else find the new where syntax less than satisfactory?

I explained the overall motivation for the where syntax in this StackOverflow answer: Partly quoting from there (with some clarifications and edits): Fundamentally, the problem with F{T}(args...) in Julia 0.5 and earlier is that the F{T} part is ambiguous – the parser knows what it means from the broader context, but its meaning depends heavily on that context. The fact that it can mean such different things is pretty confusing: In most contexts, F{T} means the parametric type F with type…

Also, Foo{Number}(3) does not work with your code in 0.6. Could it be the result of earlier experimentation?