Vector as exponent with the Euler's number basis

New to Julia
1

That is a very basic question. In Matlab, we can pass a vector for the exp function and it returns a vector with the exponential results.

In Julia, I can’t do that since exp does not allow a vector as input. Plus, I can’t do e.^v since the Euler’s number is not defined. How to solve it?

2 
julia> exp.(rand(10))
10-element Vector{Float64}:
 1.5873169230522923
 1.7204554407302755
 1.9840565297531094
 2.7057478585870305
 1.3102571943681591
 1.9628991834318725
 1.2499693417272832
 1.7896481387376577
 1.23080464883015
 1.4771492869804266
2 Likes
3

For the record, Euler’s number is bound to ℯ (i.e., \euler<TAB>). So you can do

julia> ℯ.^[1,2,3]
3-element Vector{Float64}:
  2.718281828459045
  7.38905609893065
 20.085536923187668
1 Like
4

See also this section of the manual and (for further background) this blog post.