Use of squeeze function

General Usage
1

Hi ,
I am trying to understand the way how squeeze function works,
when I tried to do the following it gives me the error " squeezed dims must all be size 1"

P = 0.1*ones(Float64, 4, 9)

for i=2:4
  squeeze(P[i,:],1)
end

can somebody help me to figure this out?

2

Does the documentation help you?

squeeze(A, dims)

  Remove the dimensions specified by dims from array A. Elements of dims must
  be unique and within the range 1:ndims(A). size(A,i) must equal 1 for all i
  in dims.

     Example
    ≡≡≡≡≡≡≡≡≡

  julia> a = reshape(collect(1:4),(2,2,1,1))
  2×2×1×1 Array{Int64,4}:
  [:, :, 1, 1] =
   1  3
   2  4
  
  julia> squeeze(a,3)
  2×2×1 Array{Int64,3}:
  [:, :, 1] =
   1  3
   2  4

In your case P[i,:] already returns a Vector what do you want to squeeze there?

1 Like
3

Indexing like that already squeezes the array for you automatically.

julia> r = rand(2,3,2)
2×3×2 Array{Float64,3}:
[:, :, 1] =
 0.292798  0.0481443  0.487387
 0.563843  0.449423   0.586495

[:, :, 2] =
 0.169698  0.794598  0.823726 
 0.587734  0.798384  0.0610884

julia> r[:, 2, :]
2×2 Array{Float64,2}:
 0.0481443  0.794598
 0.449423   0.798384

Squeezing again after that will therefore fail.

If you don’t want it to squeeze, you have to index with a range:

julia> r[:,2:2,:]
2×1×2 Array{Float64,3}:
[:, :, 1] =
 0.0481443
 0.449423

[:, :, 2] =
 0.794598
 0.798384
2 Likes
4

yeah now I get it, Thanks Guys, still a beginner to Julia :slight_smile:

1 Like