Unpacking from a collection

General Usage
1

In python I could do this and the result will be as follows

>>> a, b, *c, d = [1, 2, 3, 4, 5, 6]
>>>a
1
>>>b
2
>>>c
[3, 4, 5]
>>>d
6

I know there’s unpacking in Julia and know how to use it. But the part where I can pack multiple values into c as I did in python here is were I can’t figure out yet.

Have any idea?

1 Like
2

https://github.com/JuliaLang/julia/pull/42902

1 Like
3

Thank you, can’t wait to have it on board

1 Like
4

here a rough workaround.

julia> macro splatin(e)
           pos=findfirst(el -> !(el isa Symbol), e.args[1].args) 
           L=length(e.args[1].args)
           permute!(e.args[1].args,[1:pos-1...,pos+1:L..., pos])
           R=length(e.args[2].args)
           permute!(e.args[2].args,[1:pos-1...,pos+R-L+1:R..., pos:pos+R-L...])
           return esc(e);
       end    
@splatin (macro with 1 method)

julia> @splatin (a,b, c..., d) = [1,2,3,4,5,6,7];

julia> a,b,c,d
(1, 2, [3, 4, 5, 6], 7)
5

Nice macro, but shouldn’t it be called @slurp? Splat is the opposite operation.

6

ok let’s go with @slurpin