Understanding 'TypeError'

New to Julia
1

Please consider the module below. After having defined a function E
the following lines work as expected:

Eseq = Task(E)
for _ in 0:10
    a = consume(Eseq)
    println(a," ",typeof(a))

However wrapping these lines in a function leads to a ‘TypeError’.
Why? How can I avoid this error?

module A
function E()
    D = Dict{Int, BigInt}(0=>1, -1=>0)
    i = k = 0; s = 1
    while true
        E = 0; D[k + s] = 0; s = -s
        for j in 0:i
            E += D[k]; D[k] = E; k += s
        end
        produce(E)
        i += 1
    end
end
# --- works
Eseq = Task(E)
for _ in 0:10
    a = consume(Eseq)
    println(a," ",typeof(a))
end
# --- the same wrapped in a function
# --- does not work: TypeError  
function test()
    Eseq = Task(E)
    for _ in 0::10
        consume(Eseq)
        println(a," ",typeof(a))
    end
end
test()
end
2

When asking questions, please post the actual error instead of trying to summarize it.
Your function version is very different from the global one. The error says

ERROR: TypeError: typeassert: expected Type, got Int64
Stacktrace:
 [1] test() at ./REPL[0]:24

And your line 24 is

So you wrote a type assertion instead of a range as the error message suggested.

Also note that you didn’t assign to a.

1 Like
3

0::10

Embarrasing.
I apologize.