i’m getting confused with this simple working example, for some reason i do not get my array stored in the CSV file:
and as an output i get this:
0 rows × 0 columns
i am expecting the array to be stored in the file without any problems but the file is still empty .
Without having checked this, a problem could be that you’re not actually constructing a named tuple with
(arr = arr). This expression assigns arr to arr, just within parentheses so it almost looks like a named tuple. For one element named tuples you either have to add a comma like
(arr = arr,) or I think
(; arr) also works, or the more verbose
(;arr = arr)
what about if i’m having more than one value to store which one of them is a scalar, something like this
for i = 0:4
beta = i*pi/4
and i want to save both
i tried this
but it didn’t work.
That example is a bit hard to understand. Where does
all_results come from? Your for loop overwrites
arr in each iteration, did you mean to collect elements?
Also, the syntax
(all_results=all_results;beta=[beta]) is not correct for a named tuple, the semicolon can only go at the beginning, but you don’t even need that. The semicolon is for this convenience syntax:
a = 1
b = 2
julia> nt = (; a, b)
(a = 1, b = 2)
Then you’re passing a superfluous tuple to
CSV.write, you don’t need the extra parentheses around the two arguments.
Last but not least, if you need to store a column which only consists of the same repeated scalar, try
fill(value, number_of_elements) to create such a vector.
i apologize for that
all_results i wanted to write