a=[[1],[1,2],[2,1],[2,5],[111,3],[4,1]]
6-element Vector{Vector{Int64}}:
 [1]
 [1, 2]
 [2, 1]
 [2, 5]
 [111, 3]
 [4, 1]
I want to get the index which of them contain a element named 1,but 111 is not allowed.I want to return  [1,2,3,6] .If the sub-vector contains real 1 ,I will return the index. What should I do ? Thanks very much.
             
            
              
            
           
          
            
            
              I do not know how you want to approach this as a is a vector of vectors.
Though something like this does work:
findall.(x -> x == 1, a)
 
            
              
            
           
          
            
            
              
 JorizovdZ:
 
findall.(x -> x == 1, a)
 
 
findall.(x -> x == 1, a)
6-element Vector{Vector{Int64}}:
 [1]
 [1]
 [2]
 [1]
 []
 [2]
Sorry, It cannot return the index. like [1,2,3,6]
             
            
              1 Like 
            
            
           
          
            
              
                lmiq  
              
                  
                    October 3, 2022, 12:02pm
                   
                  4 
               
             
            
              julia> findall(x -> 1 in x, a)
4-element Vector{Int64}:
 1
 2
 3
 6
 
            
              4 Likes 
            
            
           
          
            
              
                DNF  
              
                  
                    October 3, 2022, 12:02pm
                   
                  5 
               
             
            
              
 zhangchunyong:
 
a=[[1],[1,2],[2,1],[2,5],[111,3],[4,1]]
 
 
julia> findall(1 in v for v in a)
4-element Vector{Int64}:
 1
 2
 3
 6
 
            
              3 Likes 
            
            
           
          
            
            
              An alternative:
LinearIndices(a)[in.(1, a)]