I’m new to Julia (startet today), so if this question does not fit here, let me know.
My first idea was to compare Julias speed for simple calculus with other languages i know (its in this particular area much faster than Python, R and AutoIT!)
So my Julia attempt looks like this:
x = 0 for j in 1:8 @time begin for i in 1:(j*10000000) x = i * i if i == (j*10000000) print(x, "\n") end end print("Time needed for " * string(j) * " * 10^7 calculations:") end end print(x)
You see at the end of the algorithm that I print the variable x.
The output tells me that x is equal to 0, that means x is just assigned within the loop.
How do i have to change my code, so that x is globaly changed?
If you’d like to se my implementations in Python, R and AutoIT, let me know.
Do you have other suggestions for Speed-Comparison-Implementations to test various Big-O notations?