LU Factorizations in julia

#1

PA=LU
Alu=lu(A)
A\b=Alu\b
det(A)=det(Alu)

Steps to create additional table on matrix
#2

is this a question?, Please explain and provide a minimum working example to let us help you. if you are looking to do an LU factorization in julia, this code can do it:

using LinearAlgebra
(L,U) = lu(A)
2 Likes
#3

i too need more explanation, especially because the case changes

#4

Welcome to julialang!
Let’s go with steps about the Cases:

using LinearAlgebra

This calls a module to your workplace, for convention, all functions are lowercase, and all the Modules and types are CamelCase,

A=rand(20,20)
(L, U) =lu(A) 

Here I create a matrix (or 2d array), of size 20x20,
L, U are the results of the function lu(A), that performs the operation of LU decomposition

I recommend reading the official documentation, at https://docs.julialang.org/