I would like to use the function round(a, digits=2) on the GPU, but it seems that this is not possible.

Is there another function for this purpose?

Thank you in advance

I would like to use the function round(a, digits=2) on the GPU, but it seems that this is not possible.

Is there another function for this purpose?

Thank you in advance

How about this? I prefer trick of this kind:

```
roundigit2(x) = round(Int32, 100x) / 100
```

```
julia> using CUDA
julia> roundigit2(x) = round(Int32, 100x) / 100
roundigit2 (generic function with 1 method)
julia> X = CuArray(randn(100))
100-element CuArray{Float64, 1, CUDA.Mem.DeviceBuffer}:
0.9393934792087492
0.6900935059439155
-0.8939959207450046
-1.8878733700288313
⋮
0.0561743482887146
-1.4615333912881514
-0.4060048468494186
0.8475641383618252
julia> roundigit2.(X)
100-element CuArray{Float64, 1, CUDA.Mem.DeviceBuffer}:
0.94
0.69
-0.89
-1.89
⋮
0.06
-1.46
-0.41
0.85
```

Why not?

```
julia> a = CUDA.rand(2)
2-element CuArray{Float32, 1, CUDA.Mem.DeviceBuffer}:
0.30272454
0.8437567
julia> function kernel(a,b)
a[threadIdx().x] = round(b[threadIdx().x]; digits=2)
return
end
julia> b = similar(a)
2-element CuArray{Float32, 1, CUDA.Mem.DeviceBuffer}:
0.0
0.0
julia> @cuda kernel(b,a)
CUDA.HostKernel for kernel(CuDeviceVector{Float32, 1}, CuDeviceVector{Float32, 1})
julia> b
2-element CuArray{Float32, 1, CUDA.Mem.DeviceBuffer}:
0.3
0.0
```

You should include source code and error messages when opening topics like this.