out <- glm(y ~ . , family=binomial(),data=turnout) In R, above syntax works and i expected that’s similar to julia, but . is not a proper symbol in GLM.jl maybe. julia> out = glm(@formula(y ~ .), train, Binomial()) ERROR: syntax: invalid identifier name "."

Yes, still the best way. Well, the way it’s written is awkward. julia> term(:y) ~ sum(term.(names(df, Not(:y)))) FormulaTerm Response: y(unknown) Predictors: x1(unknown) x2(unknown)

dup of [image] Using all independent variables with @formula in a multiple linear model New to Julia Edit2: Ok, is working now but I need to use your solution in the in the lm() directly, instead of being able to create a @formula variable. would be nice to be able to do …

Thanks, but your solution is written at 2 years ago and i’ll very happy if there exists a better way. Is that still the best?

Ha, I guess something did change in the intervening period and I should have known Add string method for `term` JuliaStats:master ← nilshg:patch-1 opened 05:28PM - 29 Aug 20 UTC (UTC) [ni…

How to use all variable in @formula like R language?

New to Julia

nilshg September 30, 2022, 10:40am 2

dup of

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How to use all variable in @formula like R language?

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