Hello,

I have a vector V of y values describing a curve for a series of time points x; I have a threshold level Yt. How can I predict the exact x value for Yt?

Essentially: how do I interpolate Y to find X in Julia?

I can see there is a specific package (interpolations.jl) but requires the creation of a matrix first. IS there a simpler method (without the requirement of a matrix) that works on curves (rather than linear data)?

Thank you

```
V = [100.0, 118.68686748100414, 197.53957741968554, 405.39743832303634, 909.384506158371, 2298.8440311204035, 6352.7577141124375, 19137.261442828225, 61473.086836666625, 204601.00673831577, 662816.455857954, 1.3996572716346516e6, 1.9351053374287586e6, 2.0969909161631712e6, 2.1526434991115257e6, 2.1632872818975276e6, 2.1650948890150622e6, 2.1652845329468683e6, 2.165299329101924e6, 2.165299308178196e6, 2.165300516603722e6, 2.165289152377223e6]
Yt = 500000
```