I want to lazily
zip iterator. See MWE below where I applied
a before using a
pointer.(a) allocated a new vector, so I don’t want that. Is there a way to lazily do
pointer.(a) so I dont’ have to create a new vector first but still end up with
ptra being a vector of tuples?
a = rand([randstring(8) for i = 1_000_000], 100_000_000) b = rand(100_000_000) c = similar(b) ptra = collect(zip(pointer.(a), b, c))