You can just give fft the dimensions:
help?> fft
fft(A [, dims])
Performs a multidimensional FFT of the array A. The optional dims argument specifies an iterable subset of dimensions (e.g. an integer, range, tuple, or array) to transform along.
[...]
julia> m
2×5 Matrix{Float64}:
0.801514 1.21987 1.1503 1.18761 1.2485
0.807469 1.22325 1.14981 1.1877 1.24861
julia> fft(m, (1,)) # first dimension is the column, since julia is column major
2×5 Matrix{ComplexF64}:
1.60898+0.0im 2.44312+0.0im 2.30011+0.0im 2.37531+0.0im 2.49711+0.0im
-0.005955+0.0im -0.00338+0.0im 0.00049+0.0im -9.0e-5+0.0im -0.00011+0.0im
In general, if you type ? at the julia REPL, you’ll enter help mode, where you can enter e.g. the name of a function and it’ll print any associated documentation attached to that function (if any is made available by the package developers).
As an aside, it’s a little hard to read what output you expected, please surround your code in the future with triple backticks (```) to mark them as code 
For more information about making it easier for people to help you, please refer to this thread: Please read: make it easier to help you