Hi, I’m trying to find where the elements of an Array{Int64,1} are indexed in another Array{Int64,1}. I’m trying something like the following (but b and a are much longer). b = [7;3]; a = 1:10; c = findall((in)(b), a); c = [3;7] Is there a way to have this sorted? i.e I want c to be [7;3].

You want a different operation entirely: indexin . julia> indexin(b, a) 3-element Array{Union{Nothing, Int64},1}: 1 6 4

Findall((in)) returns non-sorted array for Int64

Tamas_Papp February 7, 2019, 5:16pm 2

It is sorted — in ascending order. Use reverse(c).

Topic		Replies	Views
Built in function to sort the results of index in General Usage array	2	329	May 6, 2021
Finding Position of Element in an Array General Usage question	46	105573	October 9, 2019
Find position of Array elements in another Array General Usage indexing , arrays	16	3608	February 1, 2023
Finding the index where the values in one array are greater than the values in another array New to Julia	2	3033	July 3, 2020
Indexin() for two identical vectors New to Julia	2	491	August 13, 2018