Findall((in)) returns non-sorted array for Int64

New to Julia
#1

Hi,

I’m trying to find where the elements of an Array{Int64,1} are indexed in another Array{Int64,1}. I’m trying something like the following (but b and a are much longer).

b = [7;3];
a = 1:10;
c = findall((in)(b), a);

c = [3;7]

Is there a way to have this sorted? i.e I want c to be [7;3].

#2

It is sorted — in ascending order. Use reverse(c).

PS: also, please quote your code.

#3

Hi, unfortunately that doesn’t work - i think i wasn’t clear in my example, here’s a better one. a is not in ascending order, it is just an Array of random integers and b has more than 2 elements. See the following example:

a = [3;11;18;7;27;5];
b = [3;5;7];
c = findall((in)(b),a);

c
3-element Array{Int64,1}:
 1
 4
 6

reverse(c)
3-element Array{Int64,1}:
 6
 4
 1

But i want it to return [1;6;4] of course.

#4

You want a different operation entirely: indexin.

julia> indexin(b, a)
3-element Array{Union{Nothing, Int64},1}:
 1
 6
 4
3 Likes
#5

great, thanks!