Hi, I’ve searched for something in libraries like Dates and AstroTime, but maybe missed it as I’m surprised not to find it. I would like to find the decimal time from a date, hour, minute, second, e.g.: DateTime(2018,1,2,9,53,1) would give 2018.003828474404 This would be the reverse function fro…

Aside from getting the year, which is in Dates module, getting the partial year can be done as follows (note the endless trickiness with dates requires care not to make bugs): modyear(d) = (d - firstdayofyear(d)) / (lastdayofyear(d)+Day(1) - firstdayofyear(d)) With this function: julia> d = Da…

The yeardecimal function from DateFormats goes in both direction, DateTime ↔ decimal: julia> using DateFormats julia> dt = DateTime(2018,1,2,9,53,1) 2018-01-02T09:53:01 julia> yeardecimal(dt) 2018.003867992136 julia> yr = 2018.003867992136 julia> yeardecimal(yr) 2018-01-02T09:53:01

Yay thanks ! I’ll check if the leap second is managed.

Looks like that the leap second is not managed by this package. E.g. a leap second was added the 2005/12/31; but: dt = DateTime(2005,12,31,23,59,60) ERROR: ArgumentError: Second: 60 out of range (0:59)

I think leap seconds are just not supported by Julia’s DateTimes. Probably on purpose? But idk. There can be some packages that add leap seconds support to Julia.

[image] aplavin: I think leap seconds are just not supported by Julia’s DateTimes. Probably on purpose? But idk. Link to an older thread with a detailed discussion of this topic.

Find decimal year from time

General Usage

rafael.guerra March 10, 2025, 12:34pm 7

Link to an older thread with a detailed discussion of this topic.

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Find decimal year from time

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