Convert unixtime to yyyymmdd::Int

General Usage
1

Hello, how can I make this code more optimal?

import Dates

const Unixtime = Int

function unix2yyyymmdd(unixtime::Unixtime)::Int
    datetime = Dates.unix2datetime(unixtime)
    date = floor(datetime, Dates.Day)
    str = Dates.format(date, "yyyymmdd")
    return Meta.parse(str)
end

@time unix2yyyymmdd(123)  # -> 0.000123 seconds (38 allocations: 1.805 KiB)
2

Well instead of parsing you could just use arithmetic on the parts (see accessors here: Dates · The Julia Language)
So something like:

julia> d = Date(2023, 9, 1)
julia> 10^4*d.year + 10^2*d.month + d.day
1 Like
3 
function unix2yyyymmdd(unixtime::Unixtime)::Int
    Meta.parse(Dates.unix2datetime(unixtime) |> d -> floor(d, Dates.Day) |> d->Dates.format(d,dateformat"yyyymmdd"))
end

@time unix2yyyymmdd(123)
  0.000090 seconds (17 allocations: 664 bytes)
19700101
1 Like
4 
using Dates

function u2ymd(unixtime) 
  y, m, d = yearmonthday(unix2datetime(unixtime))
  10000y + 100m + d
end

u2ymd(123)
19700101
4 Likes