Conditional for function

General Usage Performance
1

Hi, I have a conditional inside the for loop, the conditional changes the function in each loop, but first i get the error “qxloc is not defined” so add qxloc (x) = nothing;

but this does not solve the problem and the conditional does not work.

for e = 1:3
     #x1 = xnod[LaG[e,NL1], X];  x2 = xnod[LaG[e,NL2], X]
     #y1 = xnod[LaG[e,NL1], Y];  y2 = xnod[LaG[e,NL2], Y]
     #L =  hypot(x2-x1, y2-y1)

     ang1 = atan(2,4);

  
  
     if e == 1
      qxloc(x) =-2.8*sin(ang1)*cos(ang1)
      qyloc(x) =-2.8*cos(ang1)^2

     elseif e == 2

      qxloc(x) = -2*cos(ang1)^2
      qyloc(x) = 0

     elseif e == 3

      qxloc(x) = 0
      qyloc(x) = 0 

     end

     #load the function
     plot_deformada(qxloc,qyloc,)


end

How can I solve it?

2

where did you add it? You should add it outside the loop (or simply local gxloc).

can you provide a minimal example of the code and the error?

You should probably use, for example, qxloc = x -> cos(x) to assign the name qxloc to each of the possible function.

1 Like
3

Hi, It is a for loop with 3 different elements, in each element the qxloc and qyloc function changes because it is used in a BVProblem function for different conditions.

the function where change this parameter (qxloc, qyloc) is:


function diffeq1!(dydx,y,x,p)

    #            y[v_,:]          = v
    dydx[v_]   = y[t_]          # = theta
    dydx[t_]   = y[M_]/(E*I)    # = M/(EI)
    dydx[M_]   = y[V_]          # = V
    dydx[V_]   = qyloc(x)       # = qyloc   
    dydx[u_]   = y[fax_]/(A*E)  # = u
    dydx[fax_] = -qxloc(x)       # = faxial

end
4

qxloc = x → cos (x) has solved my problem, thank you very much

qxloc =   [ x -> -2.8*sin(ang1)*cos(ang1)

            x -> 0

            x -> 0]

qyloc =   [ x -> -2.8*cos(ang1)^2

            x -> 0

            x -> 0]