let’s say I have a package, which in its main directory contain a file “some_file.jl”. if I run
using MyPackage
is it possible to somehow run
include("MyPackage.some_file.jl")
I.e. run some file contained in the package?
let’s say I have a package, which in its main directory contain a file “some_file.jl”. if I run
using MyPackage
is it possible to somehow run
include("MyPackage.some_file.jl")
I.e. run some file contained in the package?
That worked, thanks a lot ![]()
Note, though, that there are contexts — particularly compiled contexts — where you won’t have access to that directory or file.
This kinda looks like eval-laundering to me — there’s lots of guidance about not using eval, but that’s effectively what it seems you’re wanting to do here. And it’s effectively what include does. You could alternatively parse that file into the module as a const value, and then just have folks explicitly eval(MyPackage.SOME_FILE), where that was just defined in the module as a const SOME_FILE = parse(read("some_file.jl", String)).
If I can guess at your root use-case, many packages implement similar functionality with a zero-argument macro.