Calling a funcion with tuple types

#1

Consider the following:

julia> f{N}(x::Type{NTuple{N,Int}}) = x
f (generic function with 1 method)

julia> g{N}(x::Type{NTuple{N,Any}}) = x
g (generic function with 1 method)

julia> f(Tuple{Int,Int})
Tuple{Int64,Int64}

julia> g(Tuple{Int,Int})
ERROR: MethodError: no method matching g(::Type{Tuple{Int64,Int64}})
Closest candidates are:
  g{N}(::Type{Tuple{Vararg{Any,N}}}) at REPL[2]:1

I would have expected g to be called. Is it because of some covariance thing with Type?

This works:

h(x::Type{T}) where T <: NTuple{N,Any} where N = x
#2

This isn’t anything specific to Type or Tuple. NTuple{2,Int} is a subtype of but isn’t NTuple{2,Any} which means that Type{NTuple{2,Int}} is not a subtype of Type{NTuple{2,Any}} in the same way as Type{Int} not being a subtype of Type{Any} or Vector{Int} not being a subtype of Vector{Any}.

#3

Thank you. The following does work on 0.5 though:

julia> g{N}(x::Type{NTuple{N}}) = x
g (generic function with 1 method)

julia> g(Tuple{Int,Float64})
Tuple{Int64,Float64}

So I thought that replacing NTuple{N} with NTuple{N, Any} would work on 0.6.

#4

The v0.5 type-system was very buggy when it came to tuples. Now it can compute with the correctly, which also forces usage of the correct formulation for describing the set:

g{T <: NTuple{N, Any}}(x::Type{T}) = x