for data like ds=Dataset(x1=[1,2,3],x2=[3,2,1]) if I want to filter rows where x1 is less than x2 then this works filter(ds, :x1, type=isless, with = :x2) but when I define a function for byrow like f(x)=x[1]< x[2] byrow(ds, f, :) # works I cannot use it with filter filter(ds, :, type=f) ERR…

after reading that " … filter(ds, cols; [view = false, type = all,...]) is the shortcut for ds[byrow(ds, type, cols; ...), :] …" julia> byrow(ds, f, :)# works 3-element Vector{Union{Missing, Bool}}: true false false I have tried the following expressions, which I would expect to give the sam…

julia> ds[Bool.(byrow(ds, f, :)),:] This doesn’t work if f returns missing.

Yes. I have seen and, in part, I had even foreseen it. But I didn’t want to linger. Perhaps, in the general case, a function would be needed to establish on a case-by-case basis whether missing is to be evaluated as true or false (or simply remain missing)… Maybe a kwarg that can be set by the …

Byrow with user defined function

Specific Domains Data

Topic		Replies	Views
Function occursin() needs a method that accepts Union{String, Missing} General Usage	12	1894	August 28, 2018
Basic function usage in Query @filter General Usage query , queryverse	9	291	May 23, 2024
Questions about filter and broadcast New to Julia question , dataframes	1	271	October 10, 2022
.! operator not filtering missings values New to Julia question , dataframes , operator	1	356	June 3, 2022
Filter a number when missing values are in column New to Julia dataframes , missing-values	23	2815	February 11, 2022

Byrow with user defined function

Related topics