All ways to define functions in Julia?

General Usage
39

I am not too sure but I would say that multiple unrelated expressions are parsed as a block so (x;y) is a valid block. You can then replace (x;y) by begin; x; y; end in the function declaration.

julia> :((x;y)) |> dump
Expr
  head: Symbol block
  args: Array{Any}((3,))
    1: Symbol x
    2: LineNumberNode
      line: Int64 1
      file: Symbol REPL[1]
    3: Symbol y
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