In the code below, I had expected the three additions at the end to produce the same type. Plus, given that the constructor of Share should throw an error when its argument is outside the range 0 to 1, I would not have expected to see a matrix of type Share with values outside that range. What is …

First, note that s .+= 1 (literally equivalent to s .= s .+ 1 can never change the type of s. It simply loops through s, adds 1 to each entry, and stores the result into the entries of s (calling convert on them before saving to ensure they are compatible). So although the entries can change, s as a…

A = A .+ 1 yields different type than A .+= 1; why?

General Usage

Joris_Pinkse April 18, 2025, 5:33pm 7

Aha!

From Overload addition assignment += operator - #2 by stevengj I deduced that x += ydoes exactly the same thing as x = x + y. This appears to be an exception.

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A = A .+ 1 yields different type than A .+= 1; why?

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