Here’s an example of what I’m trying to do: struct MyStruct x::Int end function Base.:+(s::MyStruct, a::Int) MyStruct(s.x + a) end s1 = MyStruct(5) s2 = s1 + 3 # ------ Everything above this line works ---------- # Attempting to create the following function produces: # ERROR: UndefVar…

Overload addition assignment += operator

stevengj September 17, 2019, 2:10am 2

x += y is a synonym for x = x + y in Julia, so you can’t overload it.

1 Like

A = A .+ 1 yields different type than A .+= 1; why?

Topic		Replies	Views
How to overload +=? General Usage	8	443	November 15, 2021
Overloading update operators New to Julia question	14	1858	December 18, 2018
Why is a manual in-place addition so much faster than += and .+= on range-indexed arrays? General Usage	3	5042	April 21, 2017
+= operator General Usage	12	725	May 5, 2023
Overload in place = General Usage question , base	5	295	June 14, 2023