Here’s an example of what I’m trying to do: struct MyStruct x::Int end function Base.:+(s::MyStruct, a::Int) MyStruct(s.x + a) end s1 = MyStruct(5) s2 = s1 + 3 # ------ Everything above this line works ---------- # Attempting to create the following function produces: # ERROR: UndefVar…

Overload addition assignment += operator

stevengj September 17, 2019, 2:10am 2

x += y is a synonym for x = x + y in Julia, so you can’t overload it.

1 Like

A = A .+ 1 yields different type than A .+= 1; why?

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