Hi, I wanted to ask if there more optimal way w.r.t to Performance to find the inverse of a matrix than inv() from Linear Algebra package

You might have a look at the discussion here: [image] Why re-use factorization(A) rather than inv(A) Numerics What is the advantage of first decomposing and then left dividing every time over inverting once and multiplying the inverse every time?

Alternatives to inv() in Julia

Specific Domains Numerics

JM_Beckers July 2, 2024, 11:25am 2

You might have a look at the discussion here:

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Alternatives to inv() in Julia

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