This is dangerous, as the following code doesn’t emit any warning, just give very different results (I assume due to overflowing ???)
using Combinatorics
# 4 players get exactly one ace each:
sol1 = 4 * 3 *2 * multinomial(12,12,12,12)/multinomial(13,13,13,13) # 0 .838
sol2 = 4 * 3 *2 * (multinomial(12,12,12,12)/multinomial(13,13,13,13)) # -9.47
sol3 = 4 * 3 *2 * (multinomial(BigInt(12),12,12,12)/multinomial(BigInt(13),13,13,13)) # 0.105
sol4 = 4 * 3 *2 * multinomial(BigInt(12),12,12,12)/multinomial(BigInt(13),13,13,13) # 0.105
sol5 = 4 * 3 *2 * (multinomial(BigInt(12),BigInt(12),BigInt(12),BigInt(12))/multinomial(BigInt(13),BigInt(13),BigInt(13),BigInt(13))) # 0.105