A little demo: [s] The thing I am trying to wrap my head around is that I observed that a broadcast to combine three vectors would allocate in a loop: @time for step in 1:nsteps @. U1 = U0 + dt*V0 + ((dt^2)/2)*A0; end yields 3.080494 seconds (130.00 k allocations: 4.883 MiB) The…

Why are there allocations in my loop depending upon how I set a variable?

PetrKryslUCSD January 18, 2022, 8:04pm 13

Hmm, not convinced. dt is used inside the loop, and its type is known.

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