What wrong ? range of cell fo String Array

General Usage
1 
julia> kody5[1]
"orbis sa 00-028 ul bracka 16 oddzial hotel aria w sosnowcu"

julia> findall(rx,kody5[1])
1-element Array{UnitRange{Int64},1}:
 10:15

julia> kody5[1]findall(rx,kody5[1])
ERROR: MethodError: no method matching *(::String, ::Array{UnitRange{Int64},1})
Closest candidates are:
  *(::Any, ::Any, ::Any, ::Any...) at operators.jl:538

julia>  kody5[1][10:15]
"00-028"

Paul

2

You are missing square brackets around findall.

kody5[1][findall(rx,kody5[1])]
1 Like
3

Sorry but not works

julia> kody5[1][findall(rx,kody5[1])]
ERROR: MethodError: no method matching getindex(::String, ::Array{UnitRange{Int64},1})
Closest candidates are:
  getindex(::String, ::UnitRange{Int64}) at strings/string.jl:244
  getindex(::String, ::Int64) at strings/string.jl:209
  getindex(::String, ::UnitRange{var"#s91"} where var"#s91"<:Integer) at strings/string.jl:242
  ...
Stacktrace:
 [1] top-level scope at REPL[123]:1

julia> kody5[1]
"orbis sa 00-028 ul bracka 16 oddzial hotel aria w sosnowcu"

julia> [findall(rx,kody5[1])]
1-element Array{Array{UnitRange{Int64},1},1}:
 [10:15]
4

Works like this, with spcjal 

julia> kody5[1][findall(rx,kody5[1])[]]
"00-028"
5

You are using findall, findall will always return a vector with all ranges, by using [] you are now getting only the first range, are you sure this is what you want? If this is what you want you should just use findfirst instead of findall.

6

Yes, sorry, it’s an array so you need to extract an element.