What is interaction between F.() broadcasting and keyword args?

broadcast

#1

How does F.(a, b; c=d) work with respect to broadcasting? I understand that the arguments a, b will be broadcast. What about the keyword argument?


#2

F.(a, b; c=d) is equivalent to broadcast((a,b) -> F(a, b; c=d), a, b). That is, it does not broadcast over the keyword arguments, but instead passes them inside the closure.