I found this code recently. Does anybody know what it’s supposed to do? (zip()...,)

"for z in zip()" doesn't terminate opened 06:47PM - 15 Jan 22 UTC (UTC) [stevengj] stevengj iteration ```jl for z in zip() …

Wow, interesting find. For folks who try to run this code: Ctrl-C is your friend.

Good to know that this behavior is desired! I spent some hours frustratedly trying to figure out why my program was just hanging, to find that it was because of this. This is what I was doing. I swear I copypasted it from somewhere, but I can’t find it now. It converts Dicts to NamedTuples: mydic…

[image] uniment: that this behavior is desired! I disagree and clearly at least one other person disagree @stevengj

I probably deserved to be in debugging hell for writing such horrid code to begin with. Some form of cosmic coding karma. I was thinking it could make a nice interview question to stump new hires. Is crash prevention really worth eliminating a possible interview question?

[image] uniment: nt = (; mydict...) You can just use the NamedTuple constructor: julia> NamedTuple(Dict(:a => 1, :b => 2)) (a = 1, b = 2) julia> NamedTuple(Dict()) NamedTuple()

Is this considered idiomatic? for zip! in zip() zip, zip, zip, zip!, zip!, zip! end or is this better: for (zip!, zip!!) in zip(zip(), zip(zip())) zip, zip, zip, zip!, zip!, zip!, zip!!, zip!!, zip!! end thinking of putting it into the catch branch of try...catch statements.

What does this code do?

New to Julia

uniment October 26, 2022, 8:53pm 8

Wow, it looks like I even knew this already but I forgot! Funny how that works.

1 Like

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What does this code do?

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