I’m working on a project that involves wrapping Julia functions to be used as callbacks for a C library. I don’t understand the error when I run this, but I’m new enough to Julia to be confused about whether I should expect this to work:
function f() function g()::Cvoid return nothing end g_c = @cfunction(g, Cvoid, ()); end
UndefVarError: g not defined with Julia 1.5.2 running in a Jupyter notebook.
- I see some related posts on a similar behavior with a conditionally-defined nested non-anonymous function, and this open issue.
- The actual “
g” I’m interested in is more complex, with input arguments and modifying an array defined in