I’m working on a project that involves wrapping Julia functions to be used as callbacks for a C library. I don’t understand the error when I run this, but I’m new enough to Julia to be confused about whether I should expect this to work:
function f()
function g()::Cvoid
return nothing
end
g_c = @cfunction(g, Cvoid, ());
end
I see UndefVarError: g not defined
with Julia 1.5.2 running in a Jupyter notebook.
Notes:
- I see some related posts on a similar behavior with a conditionally-defined nested non-anonymous function, and this open issue.
- The actual “
g
” I’m interested in is more complex, with input arguments and modifying an array defined inf
.