I wrote a small code (following the advices I got from other post) just for learning some things about type stability. The two first definitions of foo() are type stable. The third definition is not. However, the type unstable function runs faster and involves less allocations than type stable ones.…

Type stable code is more expensive than type unstable code. Why?

DNF January 1, 2019, 8:51pm 2

As I mentioned in the other thread, please use BenchmarkTools for benchmarking. And remember to interpolate the variables.

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