Hello

I was solving a test problem of a 1 DOF system with a friction interface. I was somewhat surprised that when I integrated the problem, Tsit5() gives very wrong results even when setting very low tolerances. Other methods like Midpoint(), which is order 2, gave a correct result. Here is my code

```
@inline function tangential(xₜ, w, N, (kₜ, μ))
# Stick regime
if (N > 0.0) && (abs(kₜ * (xₜ - w)) < μ * N)
return kₜ * (xₜ - w), w
# Slip regime
elseif (N > 0.0) && (abs(kₜ * (xₜ - w)) ≥ μ * N)
sg = sign(xₜ - w)
return sg * μ * N, xₜ - sg * μ * N / kₜ
# Lift-off
else
return 0.0, xₜ
end
end
function tangential!(T_force, w, xₜ, N, (kₜ, μ))
@inbounds for i in eachindex(xₜ)
T_force[i], w[i] = tangential(xₜ[i], w[i], N[i], (kₜ, μ))
end
end
using BenchmarkTools, Plots, DifferentialEquations
function test!(du, u, p, t)
T, w = p
tangential!(T, w, [u[1]], [10.0], (5.0, 0.3))
du[1] = u[2]
du[2] = 5sin(t) - T[1]
end
u0 = [0.0, 0.0]
p = ([0.0], [0.0])
tspan = (0, 20π)
prob = ODEProblem(test!, u0, tspan, p)
# sol = solve(prob, Tsit5())
sol = solve(prob, Midpoint())
plot(sol)
```

The first two functions define the expression of the friction force and an inplace function that modifies the value of the force and the `w`

that holds the memory of the friction cycle (This inplace functions is thought for larger dimensional problems, I know in 1D it does not make much sense).

Then I define my ODEProblem and after solving it, I find that it does not throw the correct answer using Tsit5() (as I said, even at lower tolerances it fails).

Anybody has any idea why this could happen?

Thank you in advance