Send file with HTTP.post

General Usage
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1

Hi everyone,

I’m looking to upload files via an API using Julia with the HTTP.jl package. Unfortunately, the API can’t retrieve my file, and I get an error:

{“code”:500,“message”:“Unable to retrieve file from request.”,“payload”:}

Here is my code (the API key is a public one for the public test API, anyone can try ;))

using HTTP

url = "https://apitest.nakala.fr/datas/uploads"

headers = 
    Dict(
        "X-API-KEY" => "01234567-89ab-cdef-0123-456789abcdef", 
        "accept" => "application/json"
    )

fileOpened = open(PATH_TO_THE_FILE, "r")    

fileCur = Dict("file" => fileOpened)

response = HTTP.post(url, files=fileCur, headers=headers)

I wrote a similar script with Python and everything seems to work:

import requests

url = "https://apitest.nakala.fr/datas/uploads"

headers = {"X-API-KEY":"01234567-89ab-cdef-0123-456789abcdef", "accept": "application/json"}

fileOpened = open(PATH_TO_THE_FILE, "rb")    

fileCur = {'file': fileOpened}

response = requests.post(url, files=fileCur, headers=headers)

print(str(response.text))

The (good) response from the server:

{“name”:“myFile.txt”,“sha1”:“35b7740a641464a2dfecd282ba0592a8a23f65a3”}

I must have made a mistake with objects sent with HTTP.post but I don’t know how to fix it… Does anyone have any ideas?

Thanks a lot!!
Josselin

2

HTTP.jl’s API is different from Python’s requests. In particular, HTTP.request (post is a convenience method for request), doesn’t know the keyword arguments files and headers.

Instead it is called as HTTP.post(url, headers, body).

I believe something like

body = HTTP.Form(Dict(:file => fileOpened))

would do the trick. See API Reference · HTTP.jl

Your headers seem fine, but maybe you need to declare

Content-Type => multipart/form-data

No guarantees though, I’m not an expert.

1 Like
3

@skleinbo thank you very much for your help, it works perfectly!!

4

That’s great! If you are happy with my answer, and feel like your problem is fully resolved, please mark it as the solution.

1 Like
5

Here is another scenario as an example for other Oxigraph users. I wanted to translate the following curl command from the Oxigraph documentation into a call to HTTP.post()
curl -X POST -T my-turtle-file.ttl -H 'Content-Type: text/turtle' "http://127.0.0.1:7878/store?default"
This worked for me:

url = "http://127.0.0.1:7878/store?default"
headers = ["Content-Type" => "text/turtle"]
body=read("my-turtle-file", String)
HTTP.post(url, headers=headers, body=body)