I am trying to write some code that computes some number up to some precision and prints it with the correct number of digits. I tried the following: using Printf function print_number(x, err) numofdigits = ceil(Int, -log10(err)) @printf("%.*f ± %.*f\n", numofdigits, x, numofdigits, err) e…

Don’t use @printf, use format + Format: julia> using Printf julia> function print_number(x, err) numofdigits = ceil(Int, -log10(err)) Printf.format(Printf.Format("%.$(numofdigits)f ± %.$(numofdigits)f\n"), x, err) end print_number (generic function with 1 method) juli…

Thanks! So I understand that the * character is not supported in Julia. Do you think this should be stated somewhere in the documentation?

I’m not familiar with the internals of the Printf module, but it’d appear it doesn’t work, so yes, it may be worth mentioning it in the documentation.

Thanks! I looked for existing threads in this forum but wasn’t able to find that one. (I could just have looked in the issues of the Printf package, silly of me…)

[image] Maurizio_Tomasi: Do you think this should be stated somewhere in the documentation? [image] giordano: so yes, it may be worth mentioning it in the documentation. Most flags that have some dynamic interpretation aren’t supported (we do some length checking to make sure the forma…

Printf with variable number of digits

General Usage

rafael.guerra January 26, 2023, 7:20pm 5

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Printf with variable number of digits

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