I am trying to write some code that computes some number up to some precision and prints it with the correct number of digits. I tried the following: using Printf function print_number(x, err) numofdigits = ceil(Int, -log10(err)) @printf("%.*f ± %.*f\n", numofdigits, x, numofdigits, err) e…

Don’t use @printf, use format + Format: julia> using Printf julia> function print_number(x, err) numofdigits = ceil(Int, -log10(err)) Printf.format(Printf.Format("%.$(numofdigits)f ± %.$(numofdigits)f\n"), x, err) end print_number (generic function with 1 method) juli…

Printf with variable number of digits

General Usage

rafael.guerra January 26, 2023, 7:20pm 5

Linking similar post and PR.

1 Like

Topic		Replies	Views
Printf with variable format string General Usage strings , formatting , printf	14	8647	May 22, 2023
How to format float numbers in human-friendly format? New to Julia question , formatting	7	17233	March 30, 2021
Printf with width field as argument New to Julia question , formatting	8	1034	September 18, 2019
Error while formatting a specific number! New to Julia numbers , formatting	4	713	July 6, 2021
Formating Numbers New to Julia	4	2562	December 18, 2016

Printf with variable number of digits

Related topics