Performant way to create ntuple?

General Usage
2

This is performance of captured variables in closures · Issue #15276 · JuliaLang/julia · GitHub. You can work around it using a let block

using BenchmarkTools
@noinline g(x) = x[1]

function f1(M, ::Type{Val{N}}) where N
    s = 0
    for j = 1:M
        let j = j
            x = ntuple(i -> i + j, Val{N})
            s += g(x)
        end
    end
    return s
end
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