Outer constructor with default parameters

General Usage
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1

I am trying to define an outer constructor for this struct:

@with_kw struct Hijri
	year::Int64
	month::Int64
	day::Int64
	validate::Bool #TODO: should be able to initialize a Hijri with giving this parameter
end

Here is my constructor:

Hijri(year, month, day, validate=true) = Hijri(year, month, day, validate)

When I call it as follows:

Hijri(1400, 1, 1)

I get UndefVarError:

ERROR: LoadError: UndefVarError: Hijri not defined
Stacktrace:
 [1] top-level scope
   @ ~/Documents/projects/hijri/hijri-converter-julia-package/hijri_converter/src/convert.jl:288
in expression starting at /home/jafar_isbarov/Documents/projects/hijri/hijri-converter-julia-package/hijri_converter/src/convert.jl:288

When I tried to remove the optional argument from constructor:

Hijri(year, month, day) = Hijri(year, month, day, true)

I still got exactly the same error.

I have to questions:
(1) What is the reason for this error?
(2) Is there a more efficient (and clean) way of implementing optional struct fields?

2

Apparently, I was calling the function outside of the scope. The function was defined within a module, and I was calling it outside of it.

(Should I delete the question?)