a = Threads.Atomic{Int}(0); b = zeros(10) Threads.@threads for i = 1:10 a += i b[i] = Threads.threadid() end a When running this code with multiple threads , the value of variable “a” at the end of every iteration is different, certainly less than 55 though. I am unable to understand how …

(Please quote your code) Atomic variable does not mean multiple modification on them will be magically atomic, it only means that every single operations on them are atomic and also obey certain ordering guarantees. In this case a[] += i is not a single operation, it is an atomic load, an add, and …

Multithreading in Julia

General Usage

Topic		Replies	Views
Use of Atomic variables in julia New to Julia question	11	4242	October 28, 2017
Threads.@Atomic error New to Julia question	4	595	August 8, 2019
Your friendly neighbourhood multithreaded Spiderman New to Julia	0	388	November 27, 2019
Changing and accessing data in different threads General Usage question	3	333	November 22, 2021
Atomic much slower than @spawn-ed tasks Performance parallel	4	527	August 22, 2023

Multithreading in Julia

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