Metaprogramming - defining a function

[kristoffer.carlsson]

@josemaria

I am still not managing to do what I want. I am calling an already existing function from within the newly created function. The existing function complains about receiving a ::Symbol instead of a value.

With trivial modifications to my code aobve

body = :(a + q * other_function(d))
other_function(x) = (println("Calling this function from inside"); x^5)

julia> eval(create_function_expr(function_name, sig, variables, body))
foobar (generic function with 1 method)

julia> foobar(1, 2.0, Int32(3))
Calling this function from inside
487.0

@josemaria

I am sure it is my wrong doing, but I got the feeling that Julia is getting in the middle, not allowing me to do what want in this particular task.

Hmm, yes maybe you are just doing it wrong. Without a clear example of what you actually want to do, it is hard to say.