Julia Integer types have a minimum and maximum value . When calculations go beyond those boundaries, results are ‘incorrect’. for i in Int8[5, 10, 15, 20] println(i, " -> ", i^2) end Result: 5 -> 25 10 -> 100 15 -> -31 20 -> -112 Question: Is there an efficient way in Julia to raise an exc…

See [image] Discussion about integer overflow Internals & Design Yes, it is a limitation but I would not call it big since we could use BigInt if Int64 is not enough and an overflow is something we can catch. I find more worrying this: > julia> 1 / 10^20000 > Inf I’d …

Maximum value for Julia integer types

General Usage

nilshg May 5, 2023, 8:14am 2

See

and all the other discussions linked therein - it’s probably not productive to rehash this lenghty discussion.

One direct answer to your question is

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