List files

New to Julia
,
1

Hi,

which command can we use for list files (shell script) in Julia Terminal Windows?

Best!

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2

readdir

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3 
 readdir()
8-element Array{String,1}:
 ".gitignore"
 ".travis.yml"
 "docs"
 "LICENSE"
 "README.md"
 "REQUIRE"
 "src"
 "test"

I cannot find the name of folder and more infos.

1 Like
4

I recommend you to read https://docs.julialang.org/en/latest/base/file/ part of the Julia manual.

I understand you want something like:

print("Current directory: ", pwd())
foreach(readdir()) do f
       println("\nObject: ", f)
       dump(stat(f)) # you can customize what you want to print
end
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5

You can get the name of the folder you are currently working in with

pwd()
6

in ubuntu terminal, if we use “ls” command in a folder , it shows all names of file and sub-folders in this folder.

7

Run:

run(`ls`)

or

read(`ls`, String)

to fetch the output

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8

src and test are subfolders.

9

I have a problem with this. I have a folder with files named as “file_1”, “file_2” and so on until “file_1000”. When I use readdir i get a list of all the files in the order:
["file_1", "file_10", "file_100",..., "file_1000"]
whereas I want them in the ascendant normal order:
["file_1", "file_2", "file_3",..., "file_1000"]
Is there another way to read the files in a directory that gives a list like the one I want?

10 
julia> ls = ["file_1", "file_2", "file_10", "file_3"]
4-element Array{String,1}:
 "file_1" 
 "file_2" 
 "file_10"
 "file_3" 

julia> sort(ls, by=x->parse(Int, match(r"[0-9].*", x).match))
4-element Array{String,1}:
 "file_1" 
 "file_2" 
 "file_3" 
 "file_10"

btw, next time use ‘```’ for better readability.

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11

Check out this link

If you are generating the files and you can choose a file name my suggestion is to pad the number with zeros. The following function helps with that:

numstring(x, n=3) = string(x + 10^n)[2:end]

So in your case,

julia> fnames = "file_" .*  numstring.(1:13, 3)
13-element Array{String,1}:
 "file_001"
 "file_002"
 "file_003"
 "file_004"
 "file_005"
 "file_006"
 "file_007"
 "file_008"
 "file_009"
 "file_010"
 "file_011"
 "file_012"
 "file_013"

In the link above, Palli suggests the following procedure:

julia> split(read(`ls -1v`, String))
19-element Array{SubString{String},1}:
 "file_1" 
 "file_2" 
 "file_3" 
 "file_4" 
 "file_5" 
 "file_6" 
 "file_7" 
 "file_8" 
 "file_9" 
 "file_10"
 "file_11"
 "file_12"
 "file_13"
 "file_14"
 "file_15"
 "file_16"
 "file_18"
 "file_20"
 "file_25"
1 Like
12

Here’s a compact way to list files and directories separately:

Print files,then directories

dir = readdir()
println(‘\n’,“Files: \n”, [elm for elm in dir if !isdir(elm)])
println(‘\n’,“Directories: \n”, [elm for elm in dir if isdir(elm)])

13

You could also do:

d = readdir();
d[isdir.(d)]
d[.!isdir.(d)]
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