Hey guys, is it possible to delete a row or column from a multi-dimensional array (say a matrix) “in-place”? Somewhat similar to what deleteat! does for vectors. I guess the answer is no but I thought I’d ask (and test our new bridging system 
). Thanks in advance. (second attempt :D)
)
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No, that is not possible.
Perhaps a matrix isn’t the correct structure? This is very easy to do in DataFrames
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julia> a = [1 2; 3 4]
2×2 Array{Int64,2}:
1 2
3 4
julia> reshape(resize!(vec(a), length(a) - size(a, 1)), size(a, 1), :)
2×1 Array{Int64,2}:
1
3
It is possible, as was mentioned on slack.
This also generalizes:
Simeon Schaub:
Yes, you can just replacesize(a, 1)withsize(a)[2:end]...to always resize the last dimension of a higher-dimensional array
crstnbr:
That’s something. But it only works for the last dimension. What about the generic case, i.e dropping, say, the second column of a 1x2x3x4 sized array?
Simeon Schaub:
You should be able to use a similar approach there as well. You just need to convert whatever you want to delete to linear indices and then you can usedeleteat!after reshaping to a vector withvec
The answers don’t show up here because the bridge bot is not that smart yet.
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You can take a view.
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For those finding this post via Discourse - it is only bridged Slack → Discourse, not the other way around…
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