How to use an expression in a anonymous function?

General Usage
1

The following works:

julia> map(x -> x^2 + 2x - 1, [1,3,-1])
3-element Array{Int64,1}:
  2
 14
 -2

But I need to calculate the function dynamically.

I have:

julia> expr=Meta.parse("x^2 + 2x - 1")
:((x ^ 2 + 2x) - 1)

Now I try to use this expression in a map operation,
but it fails:

julia> map(x -> expr, [1,3,-1])
3-element Array{Expr,1}:
 :((x ^ 2 + 2x) - 1)
 :((x ^ 2 + 2x) - 1)
 :((x ^ 2 + 2x) - 1)

I tried to use eval but it doesn’t help.

julia> map(eval(x -> expr), [1,3,-1])
3-element Array{Expr,1}:
 :((x ^ 2 + 2x) - 1)
 :((x ^ 2 + 2x) - 1)
 :((x ^ 2 + 2x) - 1)

Any idea how to create an anonymous function from an expression that gives the same result as my first example?

Thank you!

Uwe

2

Found the answer myself. The following works:

julia> expr=Meta.parse("x -> x^2 + 2x - 1")
:(x->begin
          #= none:1 =#
          (x ^ 2 + 2x) - 1
      end)
julia> map(eval(expr), [1,3,-1])
3-element Array{Int64,1}:
  2
 14
 -2

Sorry for the noise!